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On fractional biparabolic inverse source problem

  • *Corresponding author: Thabet Abdeljawad

    *Corresponding author: Thabet Abdeljawad 
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  • This paper addresses a fractional biparabolic inverse source problem that integrates fractional derivatives with the biparabolic equation to achieve a more precise characterization of anomalous diffusion. We show that this problem is ill-posed according to Hadamard's sense. To tackle the instability associated with this problem, we apply regularization techniques using the Landweber iterative method. We provide convergence estimates based on a priori information on the exact solution. The paper concludes with numerical experiments that confirm the validity of the proposed theoretical framework.

    Mathematics Subject Classification: Primary: 35R30, 65F22; Secondary: 00A71, 80D23.

    Citation:

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  • Figure 1.  Diffusion rates

    Figure 2.  Exact and inexact data of Example 4.1: $ \delta = 10 \% $

    Figure 3.  The comparison of the exact solution $ f(x) $ and its regularized solution $ f^{k, \delta}(x) $ of Example 4.1: $ r = 0 $, $ \delta = 10 \% $, $ k = 20 $

    Figure 4.  The comparison of the exact solution $ f(x) $ and its regularized solution $ f^{k, \delta}(x) $ of Example 4.1: $ r = 0.5 $, $ \delta = 10 \% $, $ k = 20 $

    Figure 5.  The comparison of the exact solution $ f(x) $ and its regularized solution $ f^{k, \delta}(x) $ of Example 4.1: $ r = 1 $, $ \delta = 10 \% $, $ k = 20 $

    Figure 6.  Exact and inexact data of Example 4.1: $ \delta = 1 \% $

    Figure 7.  The comparison of the exact solution $ f(x) $ and its regularized solution $ f^{k, \delta}(x) $ of Example 4.1: $ r = 0 $, $ \delta = 1 \% $, $ k = 20 $

    Figure 8.  The comparison of the exact solution $ f(x) $ and its regularized solution $ f^{k, \delta}(x) $ of Example 4.1: $ r = 0.5 $, $ \delta = 1 \% $, $ k = 20 $

    Figure 9.  The comparison of the exact solution $ f(x) $ and its regularized solution $ f^{k, \delta}(x) $ of Example 4.1: $ r = 1 $, $ \delta = 1 \% $, $ k = 20 $

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