Relative equilibria of the 3-body problem in $ \mathbb{R}^4 $

Figure 2.  Three distinct masses $ (m_1, m_2, m_3) = (3, 2, 1)/6 $. The Lagrange equilateral family is the vertical line, not extending all the way to $ k = 1/4 $. The three non-equilateral families emerge from Euler's collinear configurations at $ k = 0 $ and for $ h \to -\infty $ approach collision configurations. The two short families have a cusp each. The long family emerges at the Euler collinear configuration with the smallest energy, then touches the endpoint of the equilateral family, and then is tangent to the maximum at $ k = 1/4 $. Past this tangency it corresponds to minimal energy at fixed $ k $ and hence is non-linearly stable

Figure 3.  Equal mass case. The Lagrange equilateral family is the vertical line, in this case extending all the way to $ k = 1/4 $. The three isosceles families coincide and emerge at the collinear Euler solution at $ k = 0 $. Isosceles triangles with $ \rho < 1 $ are non-linearly stable because they are minima in the energy for fixed $ k $

Figure 4.  Two equal masses, third mass smaller ($ \mu = 1/2 $). The Lagrange equilateral family is the vertical line, not extending all the way to $ k = 1/4 $. At the endpoint it meets the isosceles long family, which later touches $ k = 1/4 $. Both short families of asymmetric triangles emerge from a collinear Euler configuration at $ k = 0 $ and have a cusp beyond which $ h $ approaches $ -\infty $. The isosceles configurations to the left of the tangency with $ k = 1/4 $ are the absolute minimum of the energy and hence are non-linearly stable

Figure 5.  Two equal masses, third mass bigger ($ \mu = 2 $). The Lagrange equilateral family is the vertical line, not extending all the way to $ k = 1/4 $. At the endpoint it meets the long isosceles family (red), which later touches $ k = 1/4 $. One short family (green) of asymmetric triangles emerges from a collinear Euler configuration at $ k = 0 $, has a cusp tangent to the long family and retraces itself back down. The other short family (blue) of asymmetric triangles starts and finishes at the collision where $ h \to -\infty $, and has a cusp tangent to the long family. These asymmetric triangles of absolute minimal energy are non-linearly stable. There is a tiny part of the long family of symmetric isosceles triangles which have absolute minimal energy and hence are non-linearly stable

Figure 6.  Three distinct masses, somewhat close to the two isosceles cases. Left: masses $ (12, 5, 4)/21 $, Right: masses $ (6, 5, 2)/13 $. The left figure illustrates that there is no continuity in the balanced families when perturbing from the case with two equal masses and the third mass larger than the equal ones, compare Fig. 5

Figure 1.  Three smooth families of balanced configurations. Long family red, short families blue and green. Masses $ (m_1, m_2, m_3) = (3, 2, 1)/6 $. Isosceles shapes are shown as dashed blue lines. Left: $ a(b) $ for $ c = 1 $, the long family exists for all values of $ b $. Right: The extended triangle of shapes $ I = const $ with boundary black dashed where one side length vanishes. The thick black ellipse marks shapes with area $ A = 0 $ with contour lines of constant positive area inside. The other set of contour lines indicate $ V = const $. Special points are marked by their projective triple $ [a, b, c] $