$\Phi(u'(t))'=f(t,u(t),u'(t))$ on $\mathbb{R}$,
$u(-\infty)=-1,$ $u(+\infty)=1,$
with a singular $\Phi$-Laplacian operator.
We assume $f$ to
be a continuous function that satisfies suitable symmetry
conditions. Moreover some growth conditions in a neighborhood of
zero are imposed.
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